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juninha55
@juninha55
July 2022
1
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O valor de i elevado a 32 + i elevado a 9 é:
a) 1+1i
b) 2-5i
c) 3i
d) 8
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korujitos
I^32= 32/4 com resto 0
i^32=i^0=1
i^9=9/4 com resto 1
i^9=i^1= 1i
então i^32+i^9= 1+1i
divide o expoente por 4 e eleva ao resto
32÷4=8 resto 0
9÷4=2 resto 1
alternativa A
0 votes
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i^32=i^0=1
i^9=9/4 com resto 1
i^9=i^1= 1i
então i^32+i^9= 1+1i
divide o expoente por 4 e eleva ao resto
32÷4=8 resto 0
9÷4=2 resto 1
alternativa A