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famorenalima
@famorenalima
March 2022
1
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Observa a figura e determine:
a) a medida x indicada
b) a medida y indicada
c) a medida do segmento AD
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kjmaneiro
AB⇒cateto adjacente=300cm
BC⇒cateto oposto=x
ângulo=30°
tg30°=co/ca
√3/3=x/300
3x=300√3
x=300√3/3
x=100√3cm
BC⇒cateto oposto=100√3
BD⇒cateto adjacente=y
ângulo=60°
tg60°=co/ca
√3=100√3/y
y√3=100√3
y=100√3/√3
y=100cm
AD=300-100
AD=200cm
2 votes
Thanks 3
kjmaneiro
OK!
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BC⇒cateto oposto=x
ângulo=30°
tg30°=co/ca
√3/3=x/300
3x=300√3
x=300√3/3
x=100√3cm
BC⇒cateto oposto=100√3
BD⇒cateto adjacente=y
ângulo=60°
tg60°=co/ca
√3=100√3/y
y√3=100√3
y=100√3/√3
y=100cm
AD=300-100
AD=200cm