Verified answer

[tex]\LARGE\tt{}7 = 9 \: -2t \\ \LARGE\tt{}7 + 2t = 9 \\ \LARGE\tt{}2t = 9 - 7 \\ \LARGE\tt{}2t = 2 \\ \\ \LARGE\tt{}t = \dfrac{2}{2} \\ \\ {\large\boxed{\boxed{  { \LARGE \tt t = 1}}}}[/tex]

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