A) Calculer C si x vaut ½. B) développer et réduire C
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nonotata
C=(2x-5)²-(2x-5)(3x+7) c = (2*1/2 -5)² -(2*1/2 -5)(3*1/2+7) c = (2/2-5)² -(2/2 -5)(3/2 +7) c = (1-5)² -(1-5)(3/2 +14/2) c = (-4)² -(-4)(17/2) c =16 - (-68/2) c = 16 - ( -34) c = 16+34 c =50
C=(2x-5)²-(2x-5)(3x+7) c = 4x²-20x+25 -(6x²+14x-15x-35) c = 4x²-20x+25 -6x²+x+35 x = -2x² -19x+60
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c = (2*1/2 -5)² -(2*1/2 -5)(3*1/2+7)
c = (2/2-5)² -(2/2 -5)(3/2 +7)
c = (1-5)² -(1-5)(3/2 +14/2)
c = (-4)² -(-4)(17/2)
c =16 - (-68/2)
c = 16 - ( -34)
c = 16+34
c =50
C=(2x-5)²-(2x-5)(3x+7)
c = 4x²-20x+25 -(6x²+14x-15x-35)
c = 4x²-20x+25 -6x²+x+35
x = -2x² -19x+60