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Debalzac1
@Debalzac1
April 2019
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On considère l'expression D, dont une écriture est la suivante:
D=( x - 3)² - 25
1. développer et réduire l'exppression D
2. Factoriser l'expression D.
3. Calculer D pour x = √5. Donner le résultat sous la forme a + b√5.
4. Résoudre l'équation D=0
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amykim12
1) D=( x - 3)² - 25
= x² - 6x + 9 - 25
D= x² - 6x - 16
2)
D=( x - 3)² - 25
= ( x - 3 - 5 )( x - 3 + 5 )
D= ( x-8 )( x+2 )
3) D=( x - 3)² - 25
= x² - 6x - 16
= (√5)² - 6√5 - 16
= 5-6√5-16
D= -11-6√5
D= 0 donc
( x-8 )( x+2 ) = 0
Alors : Soit x-8 = 0 ou x+2=0
x=8 x=-2
2 votes
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= x² - 6x + 9 - 25
D= x² - 6x - 16
2) D=( x - 3)² - 25
= ( x - 3 - 5 )( x - 3 + 5 )
D= ( x-8 )( x+2 )
3) D=( x - 3)² - 25
= x² - 6x - 16
= (√5)² - 6√5 - 16
= 5-6√5-16
D= -11-6√5
D= 0 donc
( x-8 )( x+2 ) = 0
Alors : Soit x-8 = 0 ou x+2=0
x=8 x=-2