On donne D= ( x + 5 )( x - 1 ) - 2( 7 - x )
-montrer que D= x² + 6x - 19
-Calculer D lorsque x = -3
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BonsoirOn donne D= ( x + 5 )( x - 1 ) - 2( 7 - x )
D = x² - x +5x -5 - 14 +2x
D = x² +6x - 19
montrer que D= x² + 6x - 19
Calculer D lorsque x = -3
si x = -3
D = (-3)² + 6(-3) - 19
D = 9 - 18 - 19 = -28
= x² - x + 5x - 5 -14 +2x
= x² - x + 7x -5 -14
= x² + 6x -5-14
= x² + 6x -19
-Calculer D lorsque x = -3
D= ( x + 5 )( x - 1 ) - 2( 7 - x )
= (-3 +5 )( -3 - 1) -2( 7 - (-3))
= -3*(-3) - 3*1 +5*(-3) - 5*(-1)-2*7 - 2*(-3)
= 9 -3 - 15 -5 - 14 +6
= -22