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Sofiakhe
@Sofiakhe
April 2019
1
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On donne l'expression :
A= (x+1)(3x-2)-(x+1)(4-x)
1.) developper et reduire A
2.) factoriser A. Prendre l'expression de depart
3.) calcuker A pour x=1
4.) resoudre l'equation : A=0
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Commentaires (6)
A= (x + 1)(3x - 2) - (x + 1)(4 - x)
A= 3x² - 2x + 3x - 2 - 4x + x² - 4 + x
A= 4x² - 2x - 6
A= (x + 1)(3x - 2) - (x + 1)(4 - x)
A= (x + 1)(3x - 2 - 4 + x)
A= (x + 1)(4x - 6)
A= (1 + 1)(3*1 - 2) - (1 + 1)(4 - 1
)
A= 2 * 1 - 2 * 3
A= 2 - 6
A= - 4
(x + 1)(3x - 2) - (x + 1)(4 -
x) = 0
(x + 1)(4x - 6) = 0
x + 1 = 0 4x - 6 = 0
x = - 1 4x = 6
x = 6/4
x = 3/2
S= {- 1 ; 3/2}
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Exercice 2 et exercice 5 je n'y arive pas svpppo
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A= 3x² - 2x + 3x - 2 - 4x + x² - 4 + x
A= 4x² - 2x - 6
A= (x + 1)(3x - 2) - (x + 1)(4 - x)
A= (x + 1)(3x - 2 - 4 + x)
A= (x + 1)(4x - 6)
A= (1 + 1)(3*1 - 2) - (1 + 1)(4 - 1)
A= 2 * 1 - 2 * 3
A= 2 - 6
A= - 4
(x + 1)(3x - 2) - (x + 1)(4 - x) = 0
(x + 1)(4x - 6) = 0
x + 1 = 0 4x - 6 = 0
x = - 1 4x = 6
x = 6/4
x = 3/2
S= {- 1 ; 3/2}