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Anana29
@Anana29
April 2019
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Parmi les nombres -2 ; 0 ; 1 et 2, indiquer ceux qui sont des solutions de l'équation :
2x²+5x-1=-x²+2x+2
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nonotata
Il te suffit de rempalcer ces chiffres par x et tu auras la solution donc
2x²+5x-1=-x²+2x+2
pour -2
2(-2)² +5(-2) -1 = -(-2)² +2(-2) +2
2(4) -10 -1 = -4 -4 +2
8 -11 = = -6
-3 = -6
donc 2 n est pas la solution
pour 0
2(0)² +5(0) -1 = -(0)² +2(0) +2
0 + 0 -1 = 0 +0 +2
-1 = +2
donc 0 nest pas la solution
pour 1
2(1)² +5(1) -1 = -(1)² +2(1) +2
2 + 5 -1 = -1 +2 +2
6 = 3
donc 1 n est pas la solution
pour 2
2(2)² +5(2) -1 = -(2)² +2(2) +2
8 +10 -1 = -4 +4 +2
17 = 2
donc 2 n ont plus
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2x²+5x-1=-x²+2x+2
pour -2
2(-2)² +5(-2) -1 = -(-2)² +2(-2) +2
2(4) -10 -1 = -4 -4 +2
8 -11 = = -6
-3 = -6
donc 2 n est pas la solution
pour 0
2(0)² +5(0) -1 = -(0)² +2(0) +2
0 + 0 -1 = 0 +0 +2
-1 = +2
donc 0 nest pas la solution
pour 1
2(1)² +5(1) -1 = -(1)² +2(1) +2
2 + 5 -1 = -1 +2 +2
6 = 3
donc 1 n est pas la solution
pour 2
2(2)² +5(2) -1 = -(2)² +2(2) +2
8 +10 -1 = -4 +4 +2
17 = 2
donc 2 n ont plus