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LOUdu22
@LOUdu22
April 2019
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"petit" problème pour l'exercice 2 j'espère que vous pourrez m'aider----->
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slyz007
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On applique Pythagore dans OAB
AB²=OA²+OB²
Donc OA²=AB²-OB²=5²-3²=25-9=16
Donc OA=4
OA/OD=4/7
OB/OC=3/5,5
Donc OA/OD≠OB/OC : d'après la réciproque de Thalès, (AB) et (CD) ne sont pas parallèles.
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Bonjour quelqu'un pourrait il m'aider pour l'exercice 1 et 2 de mon devoir merci d'avance ps: il y a un PDF
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Bonjour pouvez-vous m'aider pour l'exercice 1 svp,merci il y a un scann
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Verified answer
On applique Pythagore dans OABAB²=OA²+OB²
Donc OA²=AB²-OB²=5²-3²=25-9=16
Donc OA=4
OA/OD=4/7
OB/OC=3/5,5
Donc OA/OD≠OB/OC : d'après la réciproque de Thalès, (AB) et (CD) ne sont pas parallèles.