Articles
Register
Sign In
Search
Lafolledu974
@Lafolledu974
April 2019
1
82
Report
Physique . Exercice sur les masse molaire urgent svp
Please enter comments
Please enter your name.
Please enter the correct email address.
Agree to
terms and service
You must agree before submitting.
Send
Lista de comentários
Kilaro
Exercice 1 )
m=0.20g
M(Au) = 197g.mol-1
On sait que n=m/M; donc on applique
n=1.0*10^-3 mol
Exercice 2)
2.1)M(C6H12O6) = M(C)*6 + M(H)*12 + M(O)*6 soit
M(C6H12O6)=72+12+96 = 180g.mol-1
2.2)meme formule que l'exo 1!
n=2.50/180=1.4*10^-2 mol
Exercice 3
3.1)encore la formule n=m/M donc :
n=20.0/63.5=3.14*10^-1 mol
3.2)M(CO2) = M(C) + M(O)*2
M(CO2)=44g.mol-1
3.3)encore n=m/M :
n=30.0/44=6.8*10^-1mol
Exo 4 apres
0 votes
Thanks 0
Kilaro
j'avais pu de temps ! donc exercice 4 :
Kilaro
4.1)M(H3BO3)=M(H)*3+M(B)+M(O)*3 = 62g.mol-1
Kilaro
4.2)ici la formule c'est C=n/V donc n=C*V: n=2.6*10^-2*2.5*10^-1 = 6.5*10^-3 mol
Kilaro
4.3)on connais n on connais M donc n=m/M soit m=M*n;on obtient :
Kilaro
a la 4.1) c'est 63
Kilaro
non c'est bien 62 mais jenetrouve pas pour la derniere enfin je trouve 1.69*10^-4g bizarre non ?
More Questions From This User
See All
Lafolledu974
June 2021 | 0 Respostas
Responda
Lafolledu974
June 2021 | 0 Respostas
Responda
Lafolledu974
June 2021 | 0 Respostas
Responda
Lafolledu974
June 2021 | 0 Respostas
Responda
Lafolledu974
June 2021 | 0 Respostas
Responda
Lafolledu974
June 2021 | 0 Respostas
Responda
Lafolledu974
June 2021 | 0 Respostas
Responda
Lafolledu974
February 2021 | 0 Respostas
Responda
Lafolledu974
February 2021 | 0 Respostas
Responda
Lafolledu974
February 2021 | 0 Respostas
Maths 25 Quelqu'un peut il m'aider svp je ne comprends pas
Responda
Recomendar perguntas
maceocoulon
November 2022 | 0 Respostas
lblbllbl
November 2022 | 0 Respostas
naelysvannier311
November 2022 | 0 Respostas
PikaS0ra
October 2022 | 0 Respostas
andronight67
October 2022 | 0 Respostas
kim036623
October 2022 | 0 Respostas
Tocam
October 2022 | 0 Respostas
leoniecch
October 2022 | 0 Respostas
Bobjour, pourriez vous m'aider pour le tableau
lillytrsn
October 2022 | 0 Respostas
charles5022
October 2022 | 0 Respostas
×
Report "Physique . Exercice sur les masse molaire urgent svp.... Pergunta de ideia de Lafolledu974"
Your name
Email
Reason
-Select Reason-
Pornographic
Defamatory
Illegal/Unlawful
Spam
Other Terms Of Service Violation
File a copyright complaint
Description
Helpful Links
Sobre nós
Política de Privacidade
Termos e Condições
direito autoral
Contate-Nos
Helpful Social
Get monthly updates
Submit
Copyright © 2024 ELIBRARY.TIPS - All rights reserved.
Lista de comentários
m=0.20g
M(Au) = 197g.mol-1
On sait que n=m/M; donc on applique
n=1.0*10^-3 mol
Exercice 2)
2.1)M(C6H12O6) = M(C)*6 + M(H)*12 + M(O)*6 soit
M(C6H12O6)=72+12+96 = 180g.mol-1
2.2)meme formule que l'exo 1!
n=2.50/180=1.4*10^-2 mol
Exercice 3
3.1)encore la formule n=m/M donc :
n=20.0/63.5=3.14*10^-1 mol
3.2)M(CO2) = M(C) + M(O)*2
M(CO2)=44g.mol-1
3.3)encore n=m/M :
n=30.0/44=6.8*10^-1mol
Exo 4 apres