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Nasskatt
@Nasskatt
April 2019
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Pouvez vous aider pour le 19
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slyz007
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Exercice 19 :
CosCAB=AC/AB
Donc AC=AB*Cos65=6*Cos65≈2,536 cm
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kikakika1996
SinA=CB/Ab
CB= sinA*AB = sin65*6= 5.43
en uttilliisant le theoreme de pythagore :
AB^2=Ac^2+BC^2
AC^2=36-29.57=6.43
AC= 2.53
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Verified answer
Exercice 19 :CosCAB=AC/AB
Donc AC=AB*Cos65=6*Cos65≈2,536 cm
CB= sinA*AB = sin65*6= 5.43
en uttilliisant le theoreme de pythagore :
AB^2=Ac^2+BC^2
AC^2=36-29.57=6.43
AC= 2.53