Bonsoir,
Développer:
F= 4x²-9+(2x+3)(x-1)
F= 4x²-9+2x²+3x-2x-3
F= 6x²+x-12
Factoriser:
4x²-9= (2x-3)(2x+3)
Pour x= 0
F(0)= 6(0)²+0-12
F(0)= -12
Puisque 4x² - 9 = (2x+3)(2x-3) alors
f(x) = 4x² - 9+(2x+3)(x-1)
f(x) = (2x+3)(2x-3)+(2x+3)(x-1)
f(x) = (2x+3)( 2x-3 + x - 1)
f(x) = (2x+3)(3x-4)
Pour x = 0 ⇒ f(0) = 6(0)² + x - 12 = -12
f(-1.5) = (2(-1.5) + 3)( 3(-15.) + 4) = 0( -0.5) = 0
Bonne soirée
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Verified answer
Bonsoir,
Développer:
F= 4x²-9+(2x+3)(x-1)
F= 4x²-9+2x²+3x-2x-3
F= 6x²+x-12
Factoriser:
4x²-9= (2x-3)(2x+3)
Pour x= 0
F(0)= 6(0)²+0-12
F(0)= -12
Verified answer
Bonsoir,
Puisque 4x² - 9 = (2x+3)(2x-3) alors
f(x) = 4x² - 9+(2x+3)(x-1)
f(x) = (2x+3)(2x-3)+(2x+3)(x-1)
f(x) = (2x+3)( 2x-3 + x - 1)
f(x) = (2x+3)(3x-4)
Pour x = 0 ⇒ f(0) = 6(0)² + x - 12 = -12
f(-1.5) = (2(-1.5) + 3)( 3(-15.) + 4) = 0( -0.5) = 0
Bonne soirée