Pouvez vous m'aider a résoudre les équations suivantes :
a) 3:7x=0
b) 2x-3:7=1
c) (2x+3)(x+5)=15
d) (-3x+2)(x+1)=2
a) 3:7x=0
b) 2x-3:7=1
c) (2x+3)(x+5)=15
d) (-3x+2)(x+1)=2
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Si, 3/(7x) = 0, x est l'infini.
si (3 : 7) x = 0 , x = 0
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b)
2 x - 3 : 7 = 1
2 x - 3/ 7 = 1
14 x - 3 = 7
14 x = 10
x = 10/14 = 5/7
c)
(2x+3)(x+5) = 15
2 x² + 13 x + 15 = 15
2 x² + 13 x = 0
x (2x + 13) = 0
x = 0 ou 2x + 13 =0 , x = -13/2
d)
(-3x+2)(x+1)=2
-3x^2 +2x-3x + 2 = 2
-3x² -x =0
-x (3x +1) = 0
x = 0 ou 3x+1=0 => x = -1/3