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HenriettejulesDu71
@HenriettejulesDu71
April 2019
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Pouvez vous m'aider svp 76 et 77
Je n'y arrive pas du tout
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winner123
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Bonjour
N°76
E = 9 x² - 25 + ( 3 x - 5) ( 2 x + 15)
1) E = 9 x² - 25 + 6 x² + 45 x - 10 x - 75
E = 15 x² + 35 x - 100
2 a) 9 x² - 25 = identité remarquable = ( 3 x + 5) ( 3 x - 5)
2 b) E = ( 3 x - 5) ( 3 x + 5 + 2 x + 15)
E = ( 3 x - 5) ( 5 x + 20)
3) ( 3 x - 5) ( 5 x + 20) = 0
soit 3 x - 5 = 0 donc 3 x = 5 et x = 5/3
soit 5 x + 20 = 0 donc 5 x = - 20 et x = - 4
4) x = √3
E = ( 3√3 - 5) ( 5√3 + 20)
E = 45 + 23√3 - 25√3 - 100
E = - 2 √3 - 55
N) 77
1) 2.5 x - 75 > 76
2.5 x > 76 + 75
2.5 x > 151
x > 60.4
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BonjourN°76
E = 9 x² - 25 + ( 3 x - 5) ( 2 x + 15)
1) E = 9 x² - 25 + 6 x² + 45 x - 10 x - 75
E = 15 x² + 35 x - 100
2 a) 9 x² - 25 = identité remarquable = ( 3 x + 5) ( 3 x - 5)
2 b) E = ( 3 x - 5) ( 3 x + 5 + 2 x + 15)
E = ( 3 x - 5) ( 5 x + 20)
3) ( 3 x - 5) ( 5 x + 20) = 0
soit 3 x - 5 = 0 donc 3 x = 5 et x = 5/3
soit 5 x + 20 = 0 donc 5 x = - 20 et x = - 4
4) x = √3
E = ( 3√3 - 5) ( 5√3 + 20)
E = 45 + 23√3 - 25√3 - 100
E = - 2 √3 - 55
N) 77
1) 2.5 x - 75 > 76
2.5 x > 76 + 75
2.5 x > 151
x > 60.4