pouvez vous m'aider svp.... Pergunta de ideia desallychen2811

sallychen2811 @sallychen2811

July 2022 1 43 Report

pouvez vous m'aider svp

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Nebuleuseducrabe

Bonjour,

$\sqrt{(x^2+y^2)}$

II $\vec{u}$ II = $\sqrt{(5^2+(-5^2))}$

II $\vec{u}$ II = $\sqrt{(25+25)}$

II $\vec{u}$ II = $\sqrt{50}$

II $\vec{u}$ II = $5\sqrt{2}$

II $\vec{u}$ II ≈ 7,07

En espérant t'avoir aidé :)

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