Pouvez vous m'aidez svp: Développer et réduire les expressions suivantes

5 ( 3a - 6 ) + 2 ( 4 - 6a ) =

7 ( 2 - 5a ) + 3 ( 3 - a ) =

4 ( a - 4 ) + 5 ( 6 - a ) =

8 ( 7 - 6a ) + 7 ( 2 + 7a ) =

6 ( 10a - 5 ) + 20 ( 2 - 3a ) =

2a ( 5 - a ) + 3a ( 4a - 2 ) =

a ( 4a + 6 ) + 5a ( 1 - 2a ) =

3 [ 2a + 5 ( 1 - a ) + 4 ] =

a [ 3 ( 4 - 3a ) + 2 ( 3a -5 ) ] =


merci d'avance :)
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