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guilhermeleal
@guilhermeleal
July 2022
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qual a soma dos cem primeiros numeros naturais
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AntoniLAD
Verified answer
A1=1
a2=2
n=100
razão=1
an=a1+(n-1).r
a100=1+(100-1).1
a100=1+99.1
a100=100
Soma:
sn=(a1+a100).n/2
s100=(1+100).100/2
s100=101.50
s100=5050
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Guilhermeleal
December 2019 | 0 Respostas
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Lista de comentários
Verified answer
A1=1a2=2
n=100
razão=1
an=a1+(n-1).r
a100=1+(100-1).1
a100=1+99.1
a100=100
Soma:
sn=(a1+a100).n/2
s100=(1+100).100/2
s100=101.50
s100=5050