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launegomesramos1
@launegomesramos1
July 2022
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qual e a respostar dada a funcoa f(x)=x au quadrado+6x+5;determine x1ex2
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PaxOne
X²+6x+5=0,
a=1;b=6,c=5
x=-b±√∆/2a
∆=b²-4*a*c
∆=6²-4*1*5=36-20=16
x=-(6)±√16/2*1
x=-6±4/2
x1=-6+4/2=-2/2= -1
x2=-6-4/2=-10/2= -5
x²+6x+5=0
(-1)²+(6*-1)+5=0
1+(-6)+5=0
6-6=0
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a=1;b=6,c=5
x=-b±√∆/2a
∆=b²-4*a*c
∆=6²-4*1*5=36-20=16
x=-(6)±√16/2*1
x=-6±4/2
x1=-6+4/2=-2/2= -1
x2=-6-4/2=-10/2= -5
x²+6x+5=0
(-1)²+(6*-1)+5=0
1+(-6)+5=0
6-6=0