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volmirmarcos
@volmirmarcos
March 2022
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Qual é a soma dos multiplos de 10, compreendidos entre 1 e 1995
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nicoliwe
A1=10
an=1990
razão=10
n=?
an=a1+(n-1).r
1990=10+(n-1).10
1990=10+10n-10
1990-10+10=10n
n=1990/10
n=199
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an=1990
razão=10
n=?
an=a1+(n-1).r
1990=10+(n-1).10
1990=10+10n-10
1990-10+10=10n
n=1990/10
n=199