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SaraKamerone1
@SaraKamerone1
April 2019
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Quelqu'un peut-il résoudre cette equation :
(x-4)(y+2,5)=60
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danielwenin
Verified answer
(x-4)(y+2,5)=60
xy = 60
donc xy + 2,5x - 4y - 10 = 60 ou 60
+ 2,5x - 4y - 10 = 60 => 2,5x - 4y = 10
2,5x - 4y = 10
=> 2,5x - 240/x = 10 => 2,5x² - 10x - 240 = 0
y = 60/x
2,5x² - 10x - 240 = 0 => x = 12 ou x = -8
si x = 12 alors y = 60/12 = 5 => (12;5)
si x = -8 alors y = 60/-8 => y = -7,5 => (-8 ; -7,5)
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Verified answer
(x-4)(y+2,5)=60xy = 60
donc xy + 2,5x - 4y - 10 = 60 ou 60 + 2,5x - 4y - 10 = 60 => 2,5x - 4y = 10
2,5x - 4y = 10
=> 2,5x - 240/x = 10 => 2,5x² - 10x - 240 = 0
y = 60/x
2,5x² - 10x - 240 = 0 => x = 12 ou x = -8
si x = 12 alors y = 60/12 = 5 => (12;5)
si x = -8 alors y = 60/-8 => y = -7,5 => (-8 ; -7,5)