Bonjour
Cela devient
(X+2)(x+1) = (x^2 -1)
(X+2)(x+1) -(x^2-1) = 0
(X+2(x+1) -(x-1)((x+1) = 0
(X+1)(x+2-x+1) = 0
(X+1)(3) = 0
X+ 1 = 0
X = -1
Bonjour,
(x+2)(x+1)= x²-1
x²+2x+x+2= x²-1
x²-x²+3x+2+1= 0
3x+3=0
x= -3/3
x= -1
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Verified answer
Bonjour
Cela devient
(X+2)(x+1) = (x^2 -1)
(X+2)(x+1) -(x^2-1) = 0
(X+2(x+1) -(x-1)((x+1) = 0
(X+1)(x+2-x+1) = 0
(X+1)(3) = 0
X+ 1 = 0
X = -1
Verified answer
Bonjour,
(x+2)(x+1)= x²-1
x²+2x+x+2= x²-1
x²-x²+3x+2+1= 0
3x+3=0
x= -3/3
x= -1