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Leaane
@Leaane
April 2019
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Quelqu'un pourrait m'aider a mettre cette équation sous forme canonique s'il vous plait
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(2x-8)/(x-3)≥3+x/(x+1)
(2x-8)/(x-3)≥(4x+3)/(x+1)
(2x-8)/(x-3)-(4x+3)/(x+1)≥0
((2x-8)(x+1)-(4x+3)(x-3))/((x-3)(x+1))≥0
(-2x²+3x+1)/((x-3)(x+1))≥0
-1<x≤1/4(3-√(17)) ou
1/4(3+√(17))≤x<3
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(2x-8)/(x-3)≥(4x+3)/(x+1)
(2x-8)/(x-3)-(4x+3)/(x+1)≥0
((2x-8)(x+1)-(4x+3)(x-3))/((x-3)(x+1))≥0
(-2x²+3x+1)/((x-3)(x+1))≥0
-1<x≤1/4(3-√(17)) ou 1/4(3+√(17))≤x<3