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Lea1711
@Lea1711
May 2019
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Quelqu'un pourrait me factoriser cela : -4(x-0,2)*2+0,16
Merciii
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Verified answer
-4(x-0,2)² + 0,16
= 0,16 - 4(x - 0,2)²
= 0,4² - 2²(x - 0,2)²
= 0,4² - (2(x-0,2))²
= (0,4+(2(x-0,2))(0,4-(2(x-0,2))
= (0,4+2x-0,4)(0,4-2x+0,4)
= (2x)(0,8-2x)
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nini999
Bonjour :
-4(x - 0.2)² + 0.16
-2²(x - 0.2)² + (0.4)²
(0.4)² - (2x + 0.4)²
(0.4)² - (2x + 0.4)² il prend la forme de a²-b² = (a-b)(a+b)
Alors :
[(0.4) - (2x + 0.4)][(0.4) + (2x + 0.4)]
(0.4 - 2x - 0.4)(0.4 + 2x + 0.4)
(0.4 - 0.4 - 2x)(0.4 + 0.4 + 2x)
(0 - 2x)(0.8 + 2x)
-2x(0.8 + 2x)
J’espère t'avoir t'aider
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Thanks 0
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Verified answer
-4(x-0,2)² + 0,16= 0,16 - 4(x - 0,2)²
= 0,4² - 2²(x - 0,2)²
= 0,4² - (2(x-0,2))²
= (0,4+(2(x-0,2))(0,4-(2(x-0,2))
= (0,4+2x-0,4)(0,4-2x+0,4)
= (2x)(0,8-2x)
-4(x - 0.2)² + 0.16
-2²(x - 0.2)² + (0.4)²
(0.4)² - (2x + 0.4)²
(0.4)² - (2x + 0.4)² il prend la forme de a²-b² = (a-b)(a+b)
Alors :
[(0.4) - (2x + 0.4)][(0.4) + (2x + 0.4)]
(0.4 - 2x - 0.4)(0.4 + 2x + 0.4)
(0.4 - 0.4 - 2x)(0.4 + 0.4 + 2x)
(0 - 2x)(0.8 + 2x)
-2x(0.8 + 2x)
J’espère t'avoir t'aider