Quelqu'un saurait faire:Urgent!! Merci d'avance.... Pergunta de ideia deMengellem

April 2019 1 102 Report

Quelqu'un saurait faire:
$x \sqrt{2}-7=5x+6$
$3(2x-1) \leq 4(3x-3)+15$
$\frac{8-x}{6}+ \frac{2(x-1)}{3} < \frac{x+6}{2}- \frac{x}{3}$

Urgent!! Merci d'avance

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danielwenin

Verified answer

XV2 - 5x = +6 + 7 => (V2 - 5)x = 13 => x = 13/(V2 - 5) = 13(V2 + 5)/-23
6x - 3 - 12x + 12 - 15 <=0 => -6x -6 <= 0 => -6x <= 6 => x >= - 1
8 - x + 4x - 4 < 3x + 18 - 2x => 3x + 4 < x + 18 => 2x < 14 => x < 7

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