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neuzavitoriaol
@neuzavitoriaol
March 2022
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Questão de Cinemática Escalar. Alguém sabe responder? Obrigada!
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Albertook
S=s0+vot+at²/2
s=0+0+0,8.40/2
s=16m distância percorrida durante a aceleração
s=32.60=1920m
=v=0+40.0,8=32m/s
v=v0-at
0=32.0,5t
t=64s
32²=0²+2.0,5s
s=1024m
S=1936+1024=2960m=2,96km
bjs
1 votes
Thanks 3
neuzavitoriaol
Obrigada!
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Lista de comentários
s=0+0+0,8.40/2
s=16m distância percorrida durante a aceleração
s=32.60=1920m
=v=0+40.0,8=32m/s
v=v0-at
0=32.0,5t
t=64s
32²=0²+2.0,5s
s=1024m
S=1936+1024=2960m=2,96km
bjs