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aninhaand1
@aninhaand1
October 2020
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Questão de Fisico quimica…
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afonsomelo
A formula molecular da nicotina é C10 H14 N2
C10=10.12=120
H14=14.1=14
N2=14.2=28
somando os resultados vai dar 162
1mg=10⁻₃g
dessa forma:
1mol --- 162g
x --- 0,65.10⁻₃
x=4.10⁻⁶
letra a
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Lista de comentários
C10=10.12=120
H14=14.1=14
N2=14.2=28
somando os resultados vai dar 162
1mg=10⁻₃g
dessa forma:
1mol --- 162g
x --- 0,65.10⁻₃
x=4.10⁻⁶
letra a