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yumidolls
@yumidolls
June 2021
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Qui peut m'aider pour l'exercice 4 et le 5?
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Exercice 4 :
a)
x² = 12
x² - 12 = 0
(x-√12)(x+√12) = 0
(x-2√3)(x+2√3) = 0
x - 2√3 = 0
x = 2√3
x + 2√3 = 0
x = -2√3
S = {-2√3; 2√3}
b)
-5t² = 7
t² = -7/5
Le carré d'un nombre est toujours positif, il n'y a donc pas de solutions.
Exercice 5 :
ATTENTION CORRECTION DU C PLUS BAS !
ATTENTION, CORRECTION DU G PLUS BAS
Bonne soirée !
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a)
x² = 12
x² - 12 = 0
(x-√12)(x+√12) = 0
(x-2√3)(x+2√3) = 0
x - 2√3 = 0
x = 2√3
x + 2√3 = 0
x = -2√3
S = {-2√3; 2√3}
b)
-5t² = 7
t² = -7/5
Le carré d'un nombre est toujours positif, il n'y a donc pas de solutions.
Exercice 5 :
ATTENTION CORRECTION DU C PLUS BAS !
ATTENTION, CORRECTION DU G PLUS BAS
Bonne soirée !