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anniebusschaert
@anniebusschaert
January 2021
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qui peut m'aider svp
factoriser
x²-6x+9
x²+2x+1
x²-36
merci
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Christine17
Bonjour :
x²-6x+9
x²-2×x×3+3² il prend la forme de a²-2ab+b² = (a-b)²
Alors :
(x-3)² ---> (x-3)(x-3)
________________________________________
x²+2x+1
x²+2×x×1+1² il prend la forme de a²+2ab+b² = (a+b)²
Alors :
(x+1)² ---> (x+1)(x+1)
________________________________________
x²-36
x²-6² il prend la forme de a²-b² = (a-b)(a+b)
Alors :
(x-6)(x+6)
J’espère t'avoir t'aider
0 votes
Thanks 0
nini999
Verified answer
X-6x+3²=(x-3)²
(x+1)²
(x+6)(x-6)
Tu dois connaitre par coeur les 3 identités remarquables :
(A+B)²=A²+B²+2AB
(A-B)²=A²+B²-2AB
A²-B²=(A+B)(A-B)
0 votes
Thanks 0
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x²-6x+9
x²-2×x×3+3² il prend la forme de a²-2ab+b² = (a-b)²
Alors :
(x-3)² ---> (x-3)(x-3)
________________________________________
x²+2x+1
x²+2×x×1+1² il prend la forme de a²+2ab+b² = (a+b)²
Alors :
(x+1)² ---> (x+1)(x+1)
________________________________________
x²-36
x²-6² il prend la forme de a²-b² = (a-b)(a+b)
Alors :
(x-6)(x+6)
J’espère t'avoir t'aider
Verified answer
X-6x+3²=(x-3)²(x+1)²
(x+6)(x-6)
Tu dois connaitre par coeur les 3 identités remarquables :
(A+B)²=A²+B²+2AB
(A-B)²=A²+B²-2AB
A²-B²=(A+B)(A-B)