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chtilolo59
@chtilolo59
June 2021
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qui peut m aidé exercice 1 et 4 merci d avance
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vlafon
Exo 1:
1a)Produit en croix : BH = 15*10000/500= 300cm
b)BC²=BH²+CH²
BC= rac(15²+300²) = rac(90225) = 300.4cm
2)BHC=cos(300/300.4) = 0.99°
3)BH = 15*10000/200= 750cm
BC²=BH²+CH²
BC= rac(15²+750²) = rac(562725) = 750.1cm
BHC=cos(750/750.1) = 0.99°
Exo 4:
1)H2O Donc 2H + 1O
donc 2*1*u + 16*u
=3.32108
+ 26.56864
=2.988972
2)Nombre de H2O: Produit en croix
1*1/2.988972
= 3.3456
2 votes
Thanks 1
chtilolo59
merci c super simpa
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Chtilolo59
April 2019 | 0 Respostas
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1a)Produit en croix : BH = 15*10000/500= 300cm
b)BC²=BH²+CH²
BC= rac(15²+300²) = rac(90225) = 300.4cm
2)BHC=cos(300/300.4) = 0.99°
3)BH = 15*10000/200= 750cm
BC²=BH²+CH²
BC= rac(15²+750²) = rac(562725) = 750.1cm
BHC=cos(750/750.1) = 0.99°
Exo 4:
1)H2O Donc 2H + 1O
donc 2*1*u + 16*u
=3.32108 + 26.56864
=2.988972
2)Nombre de H2O: Produit en croix
1*1/2.988972 = 3.3456