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anniebusschaert
@anniebusschaert
January 2021
1
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qui peux m'aider à faire cet exercice ?
merci
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elise0201
Pour la question 1 il faut utilisé tangente
tan(acb)=ab:bc
=10/100
acb=arctan(0.1)
=environ 84 degrés
1 votes
Thanks 0
anniebusschaert
merci
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tan(acb)=ab:bc
=10/100
acb=arctan(0.1)
=environ 84 degrés