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robinbouland
@robinbouland
June 2021
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Re bonjour, pour cette équation faut il réduire au même dénominateur tout les dénominateurs ? Si oui comment ?
Pour la b)
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hauroree
Je suis pas sûre a 100%
2x-3/7=x/3+2/5
2x-x/3=2/5 + 3/7
(6x-x)/3 = 14/35 + 15/35
5x/3 = 29/35
5x= (29x3)/35
5x= 87/35
X= 87/35 x 1/5
X= 87/175
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robinbouland
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2x-3/7=x/3+2/5
2x-x/3=2/5 + 3/7
(6x-x)/3 = 14/35 + 15/35
5x/3 = 29/35
5x= (29x3)/35
5x= 87/35
X= 87/35 x 1/5
X= 87/175