rappel : √(a²) = |a|
6 + 2√5 = 5 + 2√5 + 1 = (√5 + 1)²
a = |√5 + 1| = √5 + 1 car √5 + 1 >0
6 - 2√5 = 5 -2√5 + 1 = (√5 - 1)²
b = |√5 - 1| = √5 - 1 car √5 > 1 et √5 - 1 > 0
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Verified answer
rappel : √(a²) = |a|
6 + 2√5 = 5 + 2√5 + 1 = (√5 + 1)²
a = |√5 + 1| = √5 + 1 car √5 + 1 >0
6 - 2√5 = 5 -2√5 + 1 = (√5 - 1)²
b = |√5 - 1| = √5 - 1 car √5 > 1 et √5 - 1 > 0