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Brevetripper
@Brevetripper
April 2019
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Reduis A=5√27-√12
A=(x-3)(2x+7)-5(x-3)
developpe A
factorise A
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tlbounty2009
Développement : X×2x +X×7 -3×2X -3×7 - 5 x X -5 x -3
2x ("x" est au carré. Tu mets un petit "2" en haut du "x") +7x -6x-21 -5x +15
=2x (x au carré) -4x -6
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Steffy1
Bonjour !! je pense que c'est sa :
A=5√27-√12=22.5
A=(x-3)(2x+7)-5(x-3)
A=x ×2x=2x² x × 7=7x -3 × 2x= -6x -3 × 7= -21 -5 × x= -5x -5×(-3)= 15
A=2x²+7x-6x-21-5x+15
A=2x²-4x-6
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Lista de comentários
2x ("x" est au carré. Tu mets un petit "2" en haut du "x") +7x -6x-21 -5x +15
=2x (x au carré) -4x -6
A=5√27-√12=22.5
A=(x-3)(2x+7)-5(x-3)
A=x ×2x=2x² x × 7=7x -3 × 2x= -6x -3 × 7= -21 -5 × x= -5x -5×(-3)= 15
A=2x²+7x-6x-21-5x+15
A=2x²-4x-6