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mariasimoes70485
@mariasimoes70485
January 2023
1
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Reduza a só uma potencia
(24⋅23⋅22)÷ (27÷22)
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Anjodeolhoscastanhos
(2^4⋅2^3⋅2^2)÷ (2^7÷2^2)
= 2^(4+3+2) : [2^(7-2)]
= 2^9 / 2^5
= 2^(9-5)
= 2^4
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(2^4⋅2^3⋅2^2)÷ (2^7÷2^2)
= 2^(4+3+2) : [2^(7-2)]
= 2^9 / 2^5
= 2^(9-5)
= 2^4