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deyvisonalexandre
@deyvisonalexandre
October 2020
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Resolva a inequação: 2x + 1 >5 ?
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JPaC
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Portanto
0 votes
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geiselucid
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2x + 1 > 5
1° caso
2x + 1 > 5
2x > 5- 1
2x > 4
x >
4
2
x> 2
2° caso
2x + 1 < -5
2x < -5 -1
2x < -6
x <
-6
2
x< - 3
1 votes
Thanks 0
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Lista de comentários
Verified answer
Portanto
Verified answer
2x + 1 > 51° caso
2x + 1 > 5
2x > 5- 1
2x > 4
x > 4
2
x> 2
2° caso
2x + 1 < -5
2x < -5 -1
2x < -6
x < -6
2
x< - 3