Resposta:
a)
divida por 3
x²-5x+4=0
x'=[-(-5)+√((-5)²-4*1*4)]/2= [5+√(25-16)]/2=(5+3)/2=4
x''=[-(-5)-√((-5)²-4*1*4)]/2= [5-√(25-16)]/2=(5-3)/2=1
b)
x'=[-(75)+√((75)²-4*10*(-64)]/20=[-75+√(5625+2560]/20
x'=[-75 +√(8185)]20
x''=[-(75)-√((75)²-4*10*(-64)]/20=[-75-√(5625+2560]/20
x''=[-75 -√(8185)]20
Copyright © 2024 ELIBRARY.TIPS - All rights reserved.
Lista de comentários
Resposta:
a)
3x² -15 x + 12=0
divida por 3
x²-5x+4=0
x'=[-(-5)+√((-5)²-4*1*4)]/2= [5+√(25-16)]/2=(5+3)/2=4
x''=[-(-5)-√((-5)²-4*1*4)]/2= [5-√(25-16)]/2=(5-3)/2=1
b)
Se for 10x² +75x -64=0
x'=[-(75)+√((75)²-4*10*(-64)]/20=[-75+√(5625+2560]/20
x'=[-75 +√(8185)]20
x''=[-(75)-√((75)²-4*10*(-64)]/20=[-75-√(5625+2560]/20
x''=[-75 -√(8185)]20