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Pihuitlucie
@Pihuitlucie
April 2019
1
16
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Résoudre le système suivant :
3a + b +
= 2
a - c = 3
a -
= 0
Merci de votre aide
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anylor
A = c +3
a - c /4 = 0
on remplace a par sa valeur en fonction de c
(c +3) -(c/4) = 0
(4c +12 - c)/4 = 0
4c +12 - c = 0 => 3 c = -12 =>
c = -4
donc a = -4 + 3 = -1 =>
a = -1
puis on remplace pour trouver b
3a+b +c/2 = 2
b = -3a - c /2 +2 = - 3( -1) - (-4) /2 +2 = 7
a = - 1
b = 7
c = - 4
1 votes
Thanks 1
pihuitlucie
merci beaucoup !!:D
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a - c /4 = 0
on remplace a par sa valeur en fonction de c
(c +3) -(c/4) = 0
(4c +12 - c)/4 = 0
4c +12 - c = 0 => 3 c = -12 => c = -4
donc a = -4 + 3 = -1 => a = -1
puis on remplace pour trouver b
3a+b +c/2 = 2
b = -3a - c /2 +2 = - 3( -1) - (-4) /2 +2 = 7
a = - 1
b = 7
c = - 4