Résoudre l'équation: 15 + x >et égale 2➗3 (27 + x).... Pergunta de ideia deDidi123

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April 2019 1 39 Report

Résoudre l'équation: 15 + x >et égale 2➗3 (27 + x)

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loulakar

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Bonsoir,

Résoudre l'équation:

$15 + x \ge \dfrac{2}{3 (27 + x)}$

$15 + x \ge \dfrac{2}{81 + 3x}$

$(15 + x)(81 + 3x) \ge 2$

$1215 + 45x + 81x + 3x^{2} \ge 2$

$3x^{2} + 126x + 1213 \ge 0$

$\Delta = 126^{2} - 4 \times 3 \times 1213$

$\Delta = 15876 - 14556 = 1320$

$Delta = 2\sqrt320 > 0$ deux solutions

$x_{1} =\dfrac{-126 - 2\sqrt320}{2 \times 3}[tex]x_{1} = -21 - \dfrac{\sqrt320}{3}$

$x_{2} = -21 + \dfrac{\sqrt320}{3}$

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