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Rifaza
@Rifaza
May 2019
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Résoudre les équations suivantes:
2x²-x-3=0
5x²-4x=0
Merci d'avance
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slyz007
Verified answer
Bonjour
2x²-x-3=0
Δ=1²-4*2*(-3)=1+24=25
√Δ=5
Les solutions sont x1=(1+5)/4=3/2 et x2=(1-5)/4=-1
5x²-4x=0
x(5x-4)=0
x=0 ou 5x-4=0
x=0 ou x=4/5
2 votes
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Lista de comentários
Verified answer
Bonjour2x²-x-3=0
Δ=1²-4*2*(-3)=1+24=25
√Δ=5
Les solutions sont x1=(1+5)/4=3/2 et x2=(1-5)/4=-1
5x²-4x=0
x(5x-4)=0
x=0 ou 5x-4=0
x=0 ou x=4/5