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37299475719375
@37299475719375
May 2019
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Résoudre les équations suivantes après les avoir transformées en"équations-produits"
1 : (2x+7)au carré =(3-x)(2x+7)
2 : 49x au carré -(x-1)au carré=0
3 : 81x au carré -18x+1=0
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1 : (2x+7)au carré =(3-x)(2x+7)
(2x+7)² -(3-x)(2x+7) =0
(2x+7)(2x+7-3+x) =0
(2x+7)(3x+4) =0
2x+7 =0 3x+4 =0
2x = -7 3x =-4
x = -7/2 x = -4/3
2 : 49x au carré -(x-1)au carré=0
(7x-x+1)(7x+x-1) =0
(6x+1)(8x-1) =0
6x+1 =0 8x-1 =0
6x = -1 8x =1
x = -1/6 x = 1/8
3 : 81x au carré -18x+1=0
(9x-1)² =0
9x-1 =0
9x =1
x = 1/9
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1 : (2x+7)au carré =(3-x)(2x+7)
(2x+7)² -(3-x)(2x+7) =0
(2x+7)(2x+7-3+x) =0
(2x+7)(3x+4) =0
2x+7 =0 3x+4 =0
2x = -7 3x =-4
x = -7/2 x = -4/3
2 : 49x au carré -(x-1)au carré=0
(7x-x+1)(7x+x-1) =0
(6x+1)(8x-1) =0
6x+1 =0 8x-1 =0
6x = -1 8x =1
x = -1/6 x = 1/8
3 : 81x au carré -18x+1=0
(9x-1)² =0
9x-1 =0
9x =1
x = 1/9