Résoudre:
(2x²-8)(40-2x)=0
(x+5)²+4x=(x-7)²
7x+3≤6x+2
-2-(x-2)≥8-5x
10(3x+2)≥10(x+5)
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(2x²-8)(40-2x)=0
-4 x³+80 x²+16 x-320 = 0
x= -2 ou x= 2 ou x = 20
(x+5)²+4x=(x-7)²
x²+14 x+25 = x²-14 x+49
x= 6/7
7x+3≤6x+2
-2-(x-2)≥8-5x
7 x+3≤2 (3 x+1)
x≤ -1
10(3x+2)≥10(x+5)
30 x+20≥10 x+50
x ≥ 3/2