Resous dans Q les equations ci desous
a) (3x-2)(x+5)-(3x-2)=0
b) (3x-2)2 - (2x+1)2 =0
c) |3x+4|=0
a) (3x-2)(x+5)-(3x-2)=0
b) (3x-2)2 - (2x+1)2 =0
c) |3x+4|=0
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A) 3x^2+15x-2x-10-3x+2=03x^2+10x-8=0
Delta=10^2-4*3*(-8)
Delta=100+96
Delta=196 > 0 donc 2 solutions
x1=(-10-V196)/6
x1=(-10-7V4)/6
x2=(-10+7V4)/6
B) (3x-2-2x-1)(3x-2+2x+1)=0
(x-3)(5x-1)=0
x-3=0 et 5x-1=0
x=3 et 5x=1
x=3 et x=1/5
C) 3x+4=0
3x=(-4)
x=(-4/3)
x. | -inf. -4/3. +inf
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|3x+4|. | 3x+4. O. -3x+4
Je ne suis pas sûre de la C)