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julianadossanto
@julianadossanto
April 2022
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Responda essas questões??
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AltairAlves
Verified answer
1)
Capacidade do tanque = 45 L
Quantidade de combustível (em L) para percorrer 918 km
=
2 . 45 + (2/5 . 45)
90 + 18 = 108 L
Consumo:
C = 918 : 108
C = 8,5 km/L
2) 23 = 2.(x/10) + 3.(10-x/10)
23 = 2x/10 + 30-3x/10
23 = (2x + 30 - 3x)/10
23 = (-x + 30)/10
23 . 10 = -x + 30
230 = -x + 30
-x = 230 - 30
-x = 200 . (-1)
x = -200
1 votes
Thanks 1
alan11001100
Verified answer
1)45*2=90
2*45/90=18
90+18= 108L em 918 Km
918/108=8,5Km/L
2) 2(x/10)+3(10-x/10)=23
2x/10+30-3x/10=23
2x+30-3x/10=23
30-x=230
x=-200
0 votes
Thanks 1
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Lista de comentários
Verified answer
1)Capacidade do tanque = 45 L
Quantidade de combustível (em L) para percorrer 918 km = 2 . 45 + (2/5 . 45)
90 + 18 = 108 L
Consumo:
C = 918 : 108
C = 8,5 km/L
2) 23 = 2.(x/10) + 3.(10-x/10)
23 = 2x/10 + 30-3x/10
23 = (2x + 30 - 3x)/10
23 = (-x + 30)/10
23 . 10 = -x + 30
230 = -x + 30
-x = 230 - 30
-x = 200 . (-1)
x = -200
Verified answer
1)45*2=902*45/90=18
90+18= 108L em 918 Km
918/108=8,5Km/L
2) 2(x/10)+3(10-x/10)=23
2x/10+30-3x/10=23
2x+30-3x/10=23
30-x=230
x=-200