Resposta:
[tex]Como~~ temos:\\ \\ a_1=4\\ \\ q=2\\ \\ \\ Soma~~dos~~8~~primeiros~~termos\\ \\ \\ S_n=\dfrac{a_1(q^n-1)}{q-1}\\ \\ \\ S_8=\dfrac{4.(2^8-1)}{2-1}\\ \\ \\ S_8=\dfrac{4.(256-1)}{1}\\ \\ \\ S_8=4(255)\\ \\ \boxed{S_8=1020}[/tex]
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Resposta:
[tex]Como~~ temos:\\ \\ a_1=4\\ \\ q=2\\ \\ \\ Soma~~dos~~8~~primeiros~~termos\\ \\ \\ S_n=\dfrac{a_1(q^n-1)}{q-1}\\ \\ \\ S_8=\dfrac{4.(2^8-1)}{2-1}\\ \\ \\ S_8=\dfrac{4.(256-1)}{1}\\ \\ \\ S_8=4(255)\\ \\ \boxed{S_8=1020}[/tex]