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MrLRZ
@MrLRZ
May 2019
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Salut je dois résoudre çaa
5(x+1)+3=3x²
merci de votre aide
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FreeThinker
Verified answer
salut,
5(x+1)+3=3x²
5x+5+3-3x²=0
-3x²+5x+8=8
Δ=25-4(-3*8)=121
133>0 donc deux solutions :
x1= (-b-
√Δ)/2a=(-5-√121)/(2*(-3))=-16/-6=16/6
x1=
(-b+
√Δ)/2a=(-5+√121)/
(2*(-3))
≈6/-6=-1
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Verified answer
salut,5(x+1)+3=3x²
5x+5+3-3x²=0
-3x²+5x+8=8
Δ=25-4(-3*8)=121
133>0 donc deux solutions :
x1= (-b-√Δ)/2a=(-5-√121)/(2*(-3))=-16/-6=16/6
x1= (-b+√Δ)/2a=(-5+√121)/(2*(-3))≈6/-6=-1