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Megane9
@Megane9
May 2019
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Salut, je suis bloquer sur l’exercice vous pouvez m’aider
Merci d’avance merci d’avance
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ProfdeMaths1
Verified answer
Aire de base de la pyramide :
aire=AD²=230²=
52 900 m²
volume de la pyramide
volume=aire(base)*hauteur/3
=52900*147/3=
2 592 100 m³
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inequation
Verified answer
Bonjour,
A= C x C
A= 230²
A= 52 900 m²
V= 1/3 (B x h)
V= 1/3 (230 x 147)
V= 2 592 100 m³
1 votes
Thanks 1
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Verified answer
Aire de base de la pyramide :aire=AD²=230²=52 900 m²
volume de la pyramide
volume=aire(base)*hauteur/3
=52900*147/3=2 592 100 m³
Verified answer
Bonjour,A= C x C
A= 230²
A= 52 900 m²
V= 1/3 (B x h)
V= 1/3 (230 x 147)
V= 2 592 100 m³