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Ichan
@Ichan
May 2019
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Salut, pouvez me resoudre ces expressions et m'expliquer comlent vous avez fait svp
Factorisez cette expression:
(-8x+9)²-4
Developper cette expression et reduire:
(1+2z)²+(3+3z)(4+4z)
Merci
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nadiab
Verified answer
Factorisez cette expression:
(-8x+9)²-4
(-8x+9+2)(-8x+9-2)
(-8x+11)(-8x+7)
Développer cette expression et réduire:
(1+2z)²+(3+3z)(4+4z)
1+4z+4z²+12+12z+12z+12z²
16z²+28z+13
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Ichan
16z au carre +28z +13 nan?
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Bonjour,
(-8x+9)²-4 = (9-8x)²-4 = a²-b² qu'on factorise (a-b)(a+b)
(-8x+9-2)(-8x+9+2)=
(-8x+7)(-8x+11)
Developper cette expression et reduire:
(1+2z)²+(3+3z)(4+4z)
(1+2z)² = (a+b)² =a²+2ab+b² = 1²+2(1*2z)+(2z)² = 1+4z+4z²
(3+3z)(4+4z) = double distributivité ( * =multiplier)
3*4 + 3*4z + 3z*4 + 3z*4z) = .....
apres tu fais
1+4z+4z²+(3
*4 + 3*4z + 3z*4 + 3z*4z (que tu developpes et reduis)
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Thanks 0
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Salut, besoin d'aide pour ce calcul. Je souhaite avoir des explications sur les calculs. Je compte sur vous. Merci !
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Salut , j'y arrive vraimment pas, je souhaite avoir votre aide, merci ! Cordialement, Ichan
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Verified answer
Factorisez cette expression:(-8x+9)²-4
(-8x+9+2)(-8x+9-2)
(-8x+11)(-8x+7)
Développer cette expression et réduire:
(1+2z)²+(3+3z)(4+4z)
1+4z+4z²+12+12z+12z+12z²
16z²+28z+13
(-8x+9)²-4 = (9-8x)²-4 = a²-b² qu'on factorise (a-b)(a+b)
(-8x+9-2)(-8x+9+2)=
(-8x+7)(-8x+11)
Developper cette expression et reduire:
(1+2z)²+(3+3z)(4+4z)
(1+2z)² = (a+b)² =a²+2ab+b² = 1²+2(1*2z)+(2z)² = 1+4z+4z²
(3+3z)(4+4z) = double distributivité ( * =multiplier)
3*4 + 3*4z + 3z*4 + 3z*4z) = .....
apres tu fais
1+4z+4z²+(3*4 + 3*4z + 3z*4 + 3z*4z (que tu developpes et reduis)