Bonjour,
Factoriser les expressions:
C = (6x – 2) (x + 7) + 9x² - 1
C= 2(3x-1)( x+7) +(3x-1)(3x+1)
C= (3x-1)[ 2(x+7)+3x+1 ]
C= (3x-1)(2x+14+3x+1)
C= (3x-1)(5x+8)
Résoudre C= 0
(3x-1)(5x+8)= 0
x= 1/3 ou x= -8/5 S= { -8/5 ; 1/3 }
D = x3 – x
D= x(x²-1)
D= x(x-1)(x+1)
Résoudre D= 0
x(x-1)(x+1)= 0
x= 0 ou x= 1 ou x= -1 S= { -1 ; 0 ; 1 }
E = 16 – (2x – 3)².
E= 4² - (2x-3)²
E= (4-2x+3)(4+2x-3)
E= (-2x+7)(2x+1)
Résoudre E= 0
(-2x+7)(2x+1)= 0
x= 7/2 ou x= -1/2 S = { -1/2 ; 7/2 }
bonjour,
C = (6x – 2) (x + 7) + 9x² - 1 ;
C = 2 (3x-1) (x+7) + (3x-1) (3x+1)
C = (3x-1) (2 (x+7) + (3x+1))
C = (3x-1) (2x+14+3x+1)
C = (3x-1) (5x+15)
C = 5 (3x-1) (x+3)
D = x (x²-1)
D = x (x-1) (+1)
E = 16 – (2x – 3)²
E = (4-(2x-3)) x (4+(2x-3))
E = (4-2x+3) (4+2x-3)
E = (-2x+7) (2x+1)
C = 0
5 (3x-1) (x+3) = 0
soit 3x-1 = => x = 1/3
soit x+3 = 0 => x = -3
D = 0
x (x-1) (+1) = 0
soit x = 0
soit x = 1
soit x = -1
E = 0
(-2x+7) (2x+1) = 0
soit 2x+7 = 0 => x = -7/2
soit 2x+1 = 0 => x = -1/2
:)
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Bonjour,
Factoriser les expressions:
C = (6x – 2) (x + 7) + 9x² - 1
C= 2(3x-1)( x+7) +(3x-1)(3x+1)
C= (3x-1)[ 2(x+7)+3x+1 ]
C= (3x-1)(2x+14+3x+1)
C= (3x-1)(5x+8)
Résoudre C= 0
(3x-1)(5x+8)= 0
x= 1/3 ou x= -8/5 S= { -8/5 ; 1/3 }
D = x3 – x
D= x(x²-1)
D= x(x-1)(x+1)
Résoudre D= 0
x(x-1)(x+1)= 0
x= 0 ou x= 1 ou x= -1 S= { -1 ; 0 ; 1 }
E = 16 – (2x – 3)².
E= 4² - (2x-3)²
E= (4-2x+3)(4+2x-3)
E= (-2x+7)(2x+1)
Résoudre E= 0
(-2x+7)(2x+1)= 0
x= 7/2 ou x= -1/2 S = { -1/2 ; 7/2 }
bonjour,
C = (6x – 2) (x + 7) + 9x² - 1 ;
C = 2 (3x-1) (x+7) + (3x-1) (3x+1)
C = (3x-1) (2 (x+7) + (3x+1))
C = (3x-1) (2x+14+3x+1)
C = (3x-1) (5x+15)
C = 5 (3x-1) (x+3)
D = x3 – x
D = x (x²-1)
D = x (x-1) (+1)
E = 16 – (2x – 3)²
E = (4-(2x-3)) x (4+(2x-3))
E = (4-2x+3) (4+2x-3)
E = (-2x+7) (2x+1)
C = 0
5 (3x-1) (x+3) = 0
soit 3x-1 = => x = 1/3
soit x+3 = 0 => x = -3
D = 0
x (x-1) (+1) = 0
soit x = 0
soit x = 1
soit x = -1
E = 0
(-2x+7) (2x+1) = 0
soit 2x+7 = 0 => x = -7/2
soit 2x+1 = 0 => x = -1/2
:)