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Baptistecarbonnel
@Baptistecarbonnel
April 2019
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S'ils vous plaît aider moi je comprends pas cela porte sur les identités remarquables.
C=(x+2)(x-2)-(x-3)2
E=(3x+1)(x-2)-(2x-3)2
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maudmarine
Verified answer
C = (x + 2) (x - 2) - (x - 3) 2
C = x² - 2x + 2x - 4 - (2x - 6)
C = x² - 4 - 2x + 6
C = x² - 2x + 2
E = (3x + 1) (x - 2) - (2x - 3) 2
E = 3x² - 6x + x - 2 - (4x - 6)
E = 3x² - 5x - 2 - 4x + 6
E = 3x² - 9x + 4
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paulcarbonnel
Il faut faire :
×2+2×-2×-4=×2+4
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Verified answer
C = (x + 2) (x - 2) - (x - 3) 2C = x² - 2x + 2x - 4 - (2x - 6)
C = x² - 4 - 2x + 6
C = x² - 2x + 2
E = (3x + 1) (x - 2) - (2x - 3) 2
E = 3x² - 6x + x - 2 - (4x - 6)
E = 3x² - 5x - 2 - 4x + 6
E = 3x² - 9x + 4
×2+2×-2×-4=×2+4