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ElodieDps
@ElodieDps
May 2019
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Bonjour pourriez vous m'aider sur l'exo 1 je vois pas comment en fait je suppose que il faut utiliser tan/cos/sin vu que on travaille sur ce chapitre mais je comprends rien
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Verified answer
Bonjour,
a) tan25 =18,3/NC
NC = 18,3/tan25
≈39,30m
b) si le mât est 2 fois plus long :36,60m
NC = 39,30m
tannCm = 36,3/39,3 =0,923
nCm ≈42,°7
1 votes
Thanks 0
ElodieDps
du coup c'est quoi la distance qui la sépare du mat
ElodieDps
et celle qui la sépare du haut du mat
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Verified answer
Bonjour,a) tan25 =18,3/NC
NC = 18,3/tan25
≈39,30m
b) si le mât est 2 fois plus long :36,60m
NC = 39,30m
tannCm = 36,3/39,3 =0,923
nCm ≈42,°7